But what is the logic behind this ??? I just copy pasted some source codes and experimented, but I don't get the real logic .. something related to 3d Co-ridnate geometry for sure..
does anyone know how i can save widgets to a file and take them to another computer (the internet on that one doesnt work) ? i did this with skins by downloading them in firefox and saving them to a CD but when you try this with widgets it says you need to download opera.
The widget turned out to be quite useful for solving equations numerically (as the root of a function).
At the moment, to look for f(x,y)==0 AND g(x,y)==0, I type "abs(f(x,y))+abs(g(x,y))". Sometimes with an additional sqrt(..), depending on how the neighbourhood of the root is shaped.
To make this more useful, it would be a great help to have colored isolines in the dynamic (wireframe) view, or at least different colors for positive and negative values. It's quite hard to guess from the black lines where the root might be.
"It's amazing, but everytime when the surface changes or when I move it, the old pictures keep "painted" in the window. Is there a way of reparing that?"
waaaayyyy to confusing for me lol you need to make one for idiots like to were you just click and drag it or something lol tell me if yo do ever make one for idiots
It's amazing, but everytime when the surface changes or when I move it, the old pictures keep "painted" in the window. Is there a way of reparing that?
By DIZZLE_SEGAR, # Jan 29, 2008 0:41:00 AM
By ice_syncer, # Dec 9, 2007 6:50:05 PM
2e^-6(x^2+y^2)-SQRT(0.phi)
By ice_syncer, # Dec 9, 2007 6:45:55 PM
1/tan(cos(abs(x)+abs(y)))
By thetechgeek, # Dec 6, 2007 11:51:33 PM
That is a cd (sort of.) Can someone make a penguin?
By sk8r644, # Nov 21, 2007 6:27:25 PM
sin(4*sqrt(x^2+y^2))/sqrt(x^2+y^2)
sin(4*sqrt(x^2+y^2))
abs(x^2-y^2)
0.3*sin(4*sqrt(x^2+y^2))*sqrt(x^2+y^2)
x*y(x-y)(x+y)
10*x*y(x-y)(x+y)
(x^2-y^2)
By Lali19871014, # Oct 21, 2007 9:31:24 PM
By aoe3rules, # Sep 19, 2007 1:01:11 AM
By aoe3rules, # Sep 19, 2007 0:55:41 AM
By firepower22, # Jul 3, 2007 3:10:17 AM
(tan(5x))+(cos(5y))
(sin(cos(tan(x(y(5))))))
(sin(5(x^2+y^2)))
1-(abs(y)+abs(x))
(sinh(x^2))+(cosh(y^2))-2
(sin(5(x)))+(cos(5(y)))-1
(sin(5(x^2)))+(cos(5(y^2)))-1
(tan(5x))+(cos(5y))+(sin(5x))+(cot(5y))
(x^2+y^2)^5-1
(tan(x^2))/(sec(x^-2))
0-(abs(x^2))+(abs(y^2))
1-((abs(5x))+(abs(5y)))
(sin(5x))(cos(5y))/10
(sin(5x))(cos(5y))/10-1
(sin(5(x^2(y^2))))(cos(5(x^2(y^2))))*3-0.5
1-(x^2*y^2)*4
(tan(cot(sin(cos(y(5))))))+(tan(cot(sin(cos(x(5)))))) (look at top view)
(sin(5(x)))(cos(5(y)))
x^3
(sign(x^3))
(sign(-(x^2*y^2)*1000))
-(sign(-(x^2*y^2)*1000))
1-(1/(15(x^2+y^2)))
(sign(sin(sin(10x)*sin(10y))))
does anyone know how i can save widgets to a file and take them to another computer (the internet on that one doesnt work) ? i did this with skins by downloading them in firefox and saving them to a CD but when you try this with widgets it says you need to download opera.
By aoe3rules, # Jun 28, 2007 6:50:10 PM
At the moment, to look for f(x,y)==0 AND g(x,y)==0, I type "abs(f(x,y))+abs(g(x,y))". Sometimes with an additional sqrt(..), depending on how the neighbourhood of the root is shaped.
To make this more useful, it would be a great help to have colored isolines in the dynamic (wireframe) view, or at least different colors for positive and negative values. It's quite hard to guess from the black lines where the root might be.
By Schneemann, # Jun 11, 2007 2:21:29 AM
By Jadd, # May 29, 2007 4:59:24 PM
By Archonic, # May 23, 2007 6:37:37 PM
Regards,
Benjamin
By benjamin joffe, # May 7, 2007 6:50:58 PM
SAME PROBLEM HERE!
By miron22, # May 3, 2007 6:19:43 PM
By mikeoo92, # Apr 22, 2007 8:27:10 PM
By Reggiostar, # Apr 21, 2007 3:40:39 PM
By xinhxinh, # Apr 13, 2007 10:10:02 PM
By bacau, # Apr 9, 2007 11:12:26 PM
Great work
By refrex, # Mar 12, 2007 4:39:12 PM